HCl +KOH ---> KCl + H20

hOw many moles of HCl required to produce 5.59 x 10-3 moles of KCl?

5.59x10^-3 moles

Explanation:

The balanced equation for the reaction is given below:

HCl + KOH —> KCl + H2O

Now we can obtain the number of mole of HCl required to produce 5.59x10^-3 moles of KCl as follow:

From the balanced equation above, 1 mole of HCl produced 1 mole of KCl.

Therefore, 5.59x10^-3 moles of HCl will also produce 5.59x10^-3 moles of KCl.

From the illustration made above, we can see evidently that 5.59x10^-3 moles of HCl is required to produce 5.59x10^-3 moles of KCl