What volume of SO2 is produced when 2.35 g of sulfur burns? (All volumes are measured at STP) S (s) + O2(g) →SO2(g)

1.64 L of SO₂ is produced when 2.35 g of Sulfur burns.

Explanation:

First of all, we need to write the balanced equation as,

S (s) + O₂ (g) → SO₂ (g)

Now we have to find the number of moles of sulfur by using its given mass and molar mass.

1 mol of Sulfur atoms = 32 g of sulfur

Now the given mass is 2.35 g.

So

1 mol of S produces 1 mol of SO₂.

So 0.073 mol of S produces 0.073 mol of SO₂.

At STP, 1 mol of SO₂ occupies a volume of 22.4 L.

0.073 mol of SO₂ occupies a volume of 22.4 × 0.073 = 1.64 L

So 1.64 L of SO₂ is produced.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)