363 mL of a solution of NaOH is diluted to a final of 1400mL and and the new molarity is 0.286 calculate the original molarity of the base Report your answer with 4 decimal places

The original molarity is 1,1030M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

C1= (C2 xV2)/V1

C1= ( 1400 ml x 0,286 M)/363 ml

C1=1,1030 M

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;