A sample of water is cooled from 45°C to 25°C
by the removal of 20 calories of heat. What is the
mass of the water?

1000 g

Explanation:

Given data:

Initial temperature of water = 45°C

Final temperature of water = 25°C

Heat released = 20 cal (4184×20 = 83680 j)

Mass of water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.184 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25°C - 45°C

ΔT = -20°C

83680 j = m × 4.184 j/g.°C ×20°C

83680 j = m × 83.68 j/g

m = 83680 j / 83.68 j/g

m = 1000 g

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'