Study Example 8.1 on page 321. Then, calculate the molarity of a solution made by adding 5.51 g of CaCl2 to enough water to create a solution with a total volume of 2.50 L. Enter only a numerical value in the correct number of significant figures. Use the Periodic Table that is part of your exam to calculate molar mass. Do not enter units in the answer box, but know that the symbol for the unit of this calculation is M

0.0198 M

Explanation:

Given data

Step 1: Calculate the moles of solute

The molar mass of CaCl₂ is 110.98 g/mol. The moles corresponding to 5.51 g are:

5.51 g × (1 mol/110.98 g) = 0.0496 mol

Step 2: Calculate the molarity of the solution

M = moles of solute / liters of solution

M = 0.0496 mol / 2.50 L

M = 0.0198 M

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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