The following anions can be separated by precipitation as silver salts: Cl- , Br- , I- , CrO4 2-. If Ag is added to a solution containing the four anions, each at a concentration of 0.10 M, in what order would they precipitate?Compound:
a. AgCl ksp: 1.8x10^-10
b. Ag_2_CrO_4_ksp: 1.1 x 10 ^-12
c. AgBrksp: 5.4 x10 ^ -13
d. AgIksp: 8.5 x 10 ^ -17

AgI, AgBr, AgCl and Ag₂CrO₄

Explanation:

Ksp (product solubility constant) is defined as the equilibrium constant of the general reaction:

XₐYₙ(s) → aXⁿ⁺(aq) + nYᵃ⁻(aq)

Where X is cation and Y is anion.

Ksp = [aXⁿ⁺]ᵃ [nYᵃ⁻]ⁿ

The presence of XₐYₙ(s) produce ax moles of aXⁿ⁺ and nx moles of Yᵃ⁻. Where X is the solubility of the compound.

Replacing in Ksp:

Ksp = [ax]ᵃ [nx]ⁿ

Solving for x, Solubility (S) is defined as:

For AgCl, Ag₂CrO₄, AgBr and AgI solubilities are:

= 1.34x10⁻⁵M

= 6.50x10⁻⁵M

= 7.35x10⁻⁷M

= 9.22x10⁻⁹M

The lower solubility is the first compound in precipitate, thus, order of precipitation is:

AgI, AgBr, AgCl and Ag₂CrO₄

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d