Chemistry, 07.04.2020 19:23 EssiePooh7649

75 mL of a gas is at 690 mmHg at -45°C. What will be the new volume at
STP? *

Answers: 1

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Answer from: dangrueneberg9124

56.9 mL

Explanation:

To solve this problem, we can use the equation of state for an ideal gas, which states that:

pV=nRT

where

p is the pressure of the gas

V is its volume

n is the number of moles in the gas

R is the gas constant

T is the absolute temperature of the gas

For a gas undergoing a transformation, n and R remain constant, so we can rewrite the equation as:

$\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}$

where in this case:

p_1 = 690 mmHg = 0.908 atm is the initial pressure of the gas

V_1=75 mL is the initial volume

$T_1=-45^{\circ}+273=228 K$ is the initial temperature of the gas

p_2 = 1 atm is the final pressure (at STP)

T_2 = 273 K is the final temperature (at STP)

Solving for V2, we find the final volume of the gas:

$V_2=\frac{p_1 V_1T_2}{T_1p_2}=\frac{(0.908)(75)(228)}{(273)(1)}=56.9 mL$

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

A) the enthralling of formation for pure element in its standard state is always positivehope this : )

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75 mL of a gas is at 690 mmHg at -45°C. What will be the new volume at
STP? *...

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