G An arctic weather balloon is filled with 31.0 L of helium gas inside a prep shed. The temperature inside the shed is 7. C. The balloon is then taken outside, where the temperature is -35. C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

The new volume at at temperature of -35 °C is 26.4 L

Explanation:

Step 1: Data given

Volume of the helium gas inside a prep shed = 31.0 L

The temperature inside the shed is 7.0 °C = 7+273 = 280 K

The balloon is then taken outside, where the temperature is -35. C = 273 -35 = 238K

The pressure on the balloon stays constant at exactly 1 atm

Step 2: Calculate the new volume

V1/T1 = V2/T2o

⇒with V1 = the original volume of the helium gas inside a prep shed = 31.0 L

⇒with T1 = the original temperature inside the shed = 280 K

⇒with V2 = the new volume of the helium gas inside a prep shed = TO BE DETERMINED

⇒with T2 = the decreased temperature = 238 K

31.0 L / 280 K = V2 / 238 K

V2 = (31.0L / 280K) * 238 K

V2 = 26.35 ≈ 26.4 L

The new volume at at temperature of -35 °C is 26.4 L

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answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).