Place the following in order of increasing F-A-F bond angle, where A represents the central atom in each molecule. PF3 OF2 PF4

a. PF3 < OF2 < PF4
b. OF2 < PF3 < PF4
c. PF4 < OF2 < PF3
d. PF4 < PF3 < OF2
e. OF2 < PF4 < PF3
f. PF3 < PF4 < OF2

Correct option : B

Explanation:

First compare with

there are two lone pair in but only one lone pair presen in the so more lone pair means more repulsion and hence less bond bond angle beacuse of lone pair repulsion bonded atom come closer and hence bond angle decreased .

bond angle inversely proporional to repulsion so more repulsion means less bond angle

does no exist it exist only in the form of and here assuming because in case of difficult to compare bond angle because here two different type of bond angle is present.

there is no lone pair in the so here will no be any repulsion and hence bond will be more in as compared to

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