At what temperature in Kelvin will 0.0965 moles of chlorine exert a pressure of 2.02 atm at a volume of 0.652 L?

The temperature iis 166, 44 K.

Explanation:

We use the ideal gas formula to calculate the temperature:

PV=nRT , we clear temperature and replace with the values of the problem; the constant R of the ideal gases has a value of 0.082 l atm / K mol:

T= PV/nR= 2,02 atm x 0,652 L/ 0,0965 mol x 0,082 l atm/ K mol  

T= 166, 44 K

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