. If sulphur (IV) oxide and methane are
released simultaneously at the opposite
ends of a narrow tube, the rates of
diffusion Rso, and Rch, will be in the
ratio (s = 32, O = 16, C = 12, H = 1]
(a) 4:1
(b) 2:1
(c) 1:2
(d) 1:4
hon

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o