568 cm3 of chlorine at 25° C will occupy what volume at -25° C while the pressure remains constant?

474.3 cm³

Explanation:

Given data:

Initial volume of chlorine gas = 568 cm³

Initial temperature = 25°C

Final volume = ?

Final temperature =  -25°C

Solution:

Initial temperature = 25°C (25+273 = 297 K)

Final temperature =  -25°C (-25 +273 = 248 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 568 cm³ × 248 K /297 K

V₂ = 140864 cm³.K / 297 K

V₂ = 474.3 cm³

the answer is 1 i believe