Commercial cold packs consist of solid ammonium nitrate and water. NH 4NO 3( s) absorbs 25.69 kJ of heat per mole dissolved in water. In a coffee-cup calorimeter, 3.40 g NH 4NO 3( s) is dissolved in 100.0 g of water at 21.0 °C. What is the final temperature of the solution? Assume that the solution has a specific heat capacity of 4.18 J/g•K.

The final temperature is

Explanation:

Generally number of moles is mathematically represented as

For the given compound NH 4NO 3( s)

      The molar mass would be =      

  Now substituting 14 for (molar mass of Nitrogen) , 1 for molar mass of hydrogen, 16 for molar mass of oxygen

    The molar mass of the compound  

  The mass of the compound dissolve is 3,40 g

Substituting into the above equation

Given in the question that  1 mole of NH 4NO 3( s)  absorbs 25.69kJ

                       then 0.0425 moles would absorb  x

 Now stating this mathematically

                  1 → 25.69 kJ

             0.0425 → x

cross-multiplying and making x the subject

Generally the heat energy absorbed  is mathematically denoted as

substituting  100.0 g  for m (mass of water) , 4.18 J /g.K for (Specific heat capacity)

Making the subject

               C

The initial temperature is 21.0°C

Since is been absorbed by NH 4NO 3 when it dissolves in water in mean that water losses energy so it temperature would reduce

       Therefore final temperature is

i'm assuming that it's c.) red bank..

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.