What is the molarity of 392 mL of solution that contains 0.47 mol NaCl?

1.2 M

Explanation:

Given that:

volume of NaCl = 392 mL

Convert volume in milliliters to liters

(since 1000 mL = 1L

392 mL = 392/10000 = 0.392 L)

Concentration of NaCl = ?

Amount of moles of NaCl = 0.47 moles

Recall that the concentration of a solution depends on the amount of solute dissolved in a particular volume of solvent.

I.e Concentration in mol/L =

Amount in moles / Volume in liters

= 0.47 moles / 0.392 L

= 1.199 mol/L (Round up to the nearest tenth as 1.2 M)

Note that molarity is the same as concentration in moles per litres.

Thus, the molarity of 392 mL of solution that contains 0.47 mol NaCl is 1.2 M

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.