45) 2 AgNO 3 (aq) + K 2 CrO 4 (aq) -> Ag 2 CrO 4 (s) + 2 KNO 3 (aq) How many grams of silver chromate will precipitate when 150.0 mL of 0.500 M silver nitrate is added to excess potassium chromate?

Answer : The mass of precipitate will be, 12.4 grams.

Explanation :

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical reaction is:

From then balanced chemical reaction we conclude that,

As, 2 moles of react to give 1 mole of

So, 0.075 moles of react to give mole of

Now we have to calculate the mass of

Molar mass of = 331.73 g/mole

Therefore, the mass of precipitate will be, 12.4 grams.

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