Stock solutions of nitric acid have concentration of 16.0 M. What volume of stock solution is needed to prepare 2.00 L of 2.00 M solution of nitric acid by dilution with water?
500 mL
125 mL
250 mL
32.0 mL
62.5 mL

250 mL

Explanation:

These are the variable one has to have in mind:

= 16 M

= 2 M

= 2 L = 2000 mL

Note: C = concentration; V = volume; subscript 1 = stock solution; subscript = 2 = dilution.

What we have to solve is for

Use the following equation:

x = x ⇒ = ⇒   = 250 mL

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.