When pent-1-ene is treated with mercury(II) acetate in methanol and the resulting product is reacted with NaBH4, what is the primary organic compound which results

please check the image and explanation:

Explanation:

This whole process is known as oxymercuration and demercuration.

First step is mercuration and second step is demercuration.

it is an electrophilic addition reaction and generally we take water as a solvent but here methnaol is given so instead of attacking water , methanol will attack.

In this reaction first alkene reacts with mercuric acetate (AcO–Hg–OAc)

and it formed ring with alkene because pi electron of alkene share it with mercuric acetate and there is no formation of carbocation and hence there will not be any rearrangement possible.

the formula would be mgso4

mgso[subscript]4

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.