Carbon dioxide is usually formed when gasoline is burned. If 3.00 L of CO2 is produced at a temperature of 100 °C, what is the temperature of the gas if the volume reduces to 1.00 L?

124.3K

Explanation:

Given that,

Original volume of CO2 (V1) = 3.00 L

Original temperature of CO2 (T1) = 100°C

Since unit of temperature is Kelvin, convert 100°C to Kelvin by adding 273 to 100°C

(100°C + 273K = 373K)

New volume V2 = 1.00 L

New temperature T2 = ?

Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

V1/T1 = V2/T2

3.00L/373K = 1.00L/T2

To get the value of T2, cross multiply

3.00L x T2 = 1.00L x 373K

3.00LT2 = 373LK

Divide both sides by 3.00L

3.00LT2/3.00L = 373LK/3.00L

T2 = 124.3K

Thus, the temperature of the gas becomes 124.3 Kelvin

im not exactly sure but i think its b!

the answer is b. dilution