A 2.37 l balloon contains 0.115 mil of xenon gas, Xe (g) at a pressure of 954 Torr

The temperature in the balloon is 315 K

Explanation:

The full question

A 2.37 L balloon contains 0.115 mol of xenon gas, Xe(g), at a pressure of 954 Torr. What is the temperature, in Kelvin, of the Xe in the balloon?

Step 1: Data given

Volume of the balloon = 2.37 L

Number of moles Xenon gas = 0.115 moles

Pressure of the gas = 954 torr = 954 / 760 atm = 1.25526 atm

Step 2: Calculate the temperature of the xenon gas

p*V = n*R*T

⇒with p = the pressure of wenon gas = 1.25526 atm

⇒with V = the volume of the balloon = 2.37 L

⇒with n = the number of moles of xenon = 0.115 moles

⇒with R = the gasconstant = 0.08206 L*atm/mol*K

⇒with T = the temperature in the balloon = TO BE DETERMINED

T = (p*V) / (n*R)

T = (1.25526 * 2.37)/(0.115 * 0.08206)

T = 315 K

The temperature in the balloon is 315 K

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