At stp, 32.0 liters of o2 contains the same number of molecules as what element?

12.04x10^23

Explanation:

I mole of a substance contains 6.022x10^23

Here, Molar mass of O = 16u

And molar mass of 02 32u

And 32g of 02 = 1 mole of 02

Therefore 32g of 02 has molecules = 6.022x10^23

Since 1 molecule of 02 has 2 atoms

Therefore 32g of 02 has atoms=2*6.02x10*23

= 12.04x10^23

Therefore, any element that contains 8.60 × 10^23 molecules contain the same number of molecules as 32 litres of O2 at STP.

Explanation:

At STP(standard temperature and pressure)

The volume of 1 mole of gas is 22.4 litres.

Number of molecules in 1 mole of gas is = 6.022×10^23 molecules/mole

The number of moles of O2 in 32 litres at STP;

n = 32litres ÷ 22.4 litres/mole

n = 1.429 moles of O2.

The number of molecules of O2 in 32 litres at STP is;

N = 32/22.4 moles × 6.022×10^23 molecules/mole

N = 8.60 × 10^23 molecules.

Therefore, any element that contains 8.60 × 10^23 molecules contain the same number of molecules as 32 litres of O2 at STP.