Calculate the entropy change in the surroundings associated with this reaction occurring at 25∘c.

This is an incomplete question, here is a complete question.

Consider the reaction between nitrogen and oxygen gas from dinitrogen monoxide.

Given: delta Hrxn= +163.2kJ

Calculate the entropy change in the surroundings when this reaction occurs at 25 degrees C.

Answer : The entropy change in the surroundings is, -547.6 J/K

Explanation :

Formula used to calculate the entropy change in the surroundings is:

where,

= entropy change in the surrounding

Q = heat energy

T = temperature =

Given:

Now put all the given values in the above formula, we get:

Therefore, the entropy change in the surroundings is, -547.6 J/K

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante