The equilibrium constant is given for one of the reactions below. determine the value of the missing equilibrium constant.
2 hd(g) ⇌ h2(g) + d2(g)
kc = 0.28

6 h2(g) + 6 d2(g) ⇌ 12 hd(g)
kc = ?

a) 0.00048
b) 1.2
c) 1.62
d) 2075
e) 0.81

Given the original equation of 2 HD(g) ⇌ H2(g) + D2(g)  with Kc = 0.28 and asked for the kc of the equation 6 H2(g) + 6 D2(g) ⇌ 12 HD(g), we can see that the equation 1 is reversed and multiplide by 6. in this case, the reverse means kc is equal to 1/0.28 and that the multiplication by 6 raises the new kc to 6. the new kc is equal to D. 2075

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.