Find the pH, pOH, and [H+] for a solution with a [OH-] of 10^-9 M. Is the solution acidic or basic?

pOH = 9; pH = 5; Solution is acidic

Explanation:

the -log[OH] = the pOH. this means the pOH is 9.

the pOH and the pH add up to 14. 14-9=5 so the pH is 5.

the solution is acidic because the pOH is greater then the pH.

The answer to your question is  pOH = 9, pH = 5, [H⁺] = 1 x 10⁻⁵ M, it is an acid.

Explanation:

Data

[OH⁻] = 10⁻⁹ M

pH = ?

pOH = ?

[H⁺] = ?

Process

1.- Calculate the pOH

pOH = -log [OH]

-Substitution

pOH = -log [10⁻⁹]

-Result

pOH = 9

2.- Calculate the pH

Formula

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

pH = 14 - 9

pH = 5

3.- Calculate the [H⁺]

pH = -log[H⁺]

-Substitution

5 = -log [H⁺]

-Simplification

antilog -5 = [H⁺]

-Result

[H⁺] = 1 x 10⁻⁵

4.- The solution is an acid because the pH was lower than 7.

yes, water is wet, just as it makes other things wet, it is wet itself, kinda like ice, when ice is in water, the ice makes water cold, and ice is cold, therefore with that example, water is wet

personal, she chose to do it.