Mrs. Doe and Mrs. Roe had babies at the same hospital. Mrs. Doe took home a girl, Nancy, and Mrs. Roe took home a boy, Richard. However, Mrs. Roe was sure she had a girl and brought suit against the hospital. Blood tests showed that Mr. Roe was type O, Mrs. Roe was type AB, and Mr. and Mrs. Doe were both type B. Nancy was type A and Richard was type O. Had an exchange occurred?
Write the alleles as:
Type O – ii
Type AB - IAIB
Type B – IBIB or IBi
Type A - IAIA or IAi

texas

Explanation:

rs. Doe and Mrs. Roe had babies at the same hospital. Mrs. Doe took home a girl, Nancy, and Mrs. Roe took home a boy, Richard. However, Mrs. Roe was sure she had a girl and brought suit against the hospital. Blood tests showed that Mr. Roe was type O, Mrs. Roe was type AB, and Mr. and Mrs. Doe were both type B. Nancy was type A and Richard was type O. Had an exchange occurred?

Write the alleles as:

Type O – ii

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2