What quantity of gas, in moles, is contained in 26.97L at STP?

The answer to your question is 1.09 moles

Explanation:

Data

Volume = 26.97 l

Temperature = 20°C

Pressure = 1 atm

Gas constant = 0.082 atm l / mol°K

Process

1.- Convert temperature to °K

Temperature = 26.97 + 273

                       = 299.97°K

2.- Write the formula

               PV = nRT

-solve for moles

                n = PV /RT

-substitution

                 n = (1 x 26.97) / (0.082 x 299.97)

-Simplification

                 n = 26.97 / 24.6

-Result

                 n = 1.09

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

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