A 4.75 Liter container is at a pressure of 120 kPa. What will its pressure be at a volume of 1.85L?

The answer to your question is 308.1 kPa

Explanation:

Data

Volume 1 = V1 = 4.75 l

Pressure 1 = P1 = 120 kPa

Volume 2 = V2 = 1.85 l

Pressure 2 = ?

Process

To solve this problem use Boyle's law.

                 P1V1 = P2V2

- Solve for P2

                 P2 = P1V1 / V2

- Substitution

                 P2 = (120 x 4.75) / 1.85

-Simplification

                 P2 = 570 / 1.85

-Result

                  P2 = 308.1 kPa

it's filtration, but this is an assumption so my apologies if i got this