Given the following reaction: C3H8 + 5 O2 -> 3 CO2 + 4 H2O How many moles of CO2 will be produced from 97.0 g of C3H8 assuming O2 is available in excess?

The answer to your question is 6.61 moles of CO₂

Explanation:

Data

moles of CO₂ = ?

mass of C₃H₈ = 97 g

mass of O₂ = excess

Balanced chemical reaction

               C₃H₈  +  5O₅  ⇒  3 CO₂  +  4H₂O

Process

1.- Calculate the molar mass of C₃H₈

C₃H₈ = (12 x 3) + (1 x 8) = 36 + 8 = 44 g

2.- Convert the mass to moles

                          44 g of C₃H₈ 1 mol

                           97 g of C₃H₈ x

                              x = (97 x 1) / 44

                              x = 97 / 44

                              x = 2.20 moles

3.- Calculate the moles of CO₂ using proportions and the coefficients of the balanced chemical reaction

                     1 mol of C₃H₈ 3 moles of CO₃

                     2.2 mol of C₃H₈  x

                            x = (2.2 x 3) / 1

                            x = 6.61 moles of CO₂

12 is it do you think so