When phosphorus reacts with chlorine, phosphorus trichloride is formed according to the equation

P_{4}(s) + Cl_{2}(g) → PCl_{3}(l)(unbalanced)

A) Balance the equation by filling in the correct coefficients in the equation above.

B) Determine how many grams of chlorine gas Cl_{2} would be required to react with 10.6 g of phosphorous P_{4}(Mw(P_{4})= 123.9g/mol;Mw(Cl_{2})= 70.9 g/mol. Your answer should be gram chlorine gas Cl_{2})

Mass = 38.3 g

Explanation:

Given data:

Mass of Cl₂ required = ?

Mass of phosphorus = 10.6 g

Solution:

Chemical equation:

P₄ + 6Cl₂   →   4PCl₃

Number of moles of P₄:

Number of moles = mass/ molar mass

Number of moles = 10.6 g/123.9 g/mol

Number of moles = 0.09 mol

Now we will compare the moles of P₄ with Cl₂ from balance chemical equation.

               P₄            :            Cl₂

                1             :              6

              0.09        :            6×0.09 = 0.54 mol

Mass of chlorine gas:

Mass = number of moles × molar mass

Mass = 0.54 mol × 70.9 g/mol

Mass = 38.3 g

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

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