Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 476 J as its temperature changes from 20.13 oC to 41.06 oC. (0.522 J/g oC)

The specific heat capacity of Titanium is found as 0.522 J / g°C.

Explanation:

We have to find the specific capacity using the formula as,

q = m × c × ΔT

Where,

q is the heat absorbed by the sample = 476 J

m is the mass of the sample = 43.56 g

c is the specific heat capacity of the sample = ?

ΔT is the temperature difference  = 41.06° C - 20.13°C = 20.93° C

Now, we have to rewrite the equation to get the specific heat capacity as,

c =

 =

 = 0.522 J / g°C

So the specific heat capacity of Titanium is found as 0.522 J / g°C.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

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