What is the molarity of an 85.0-mL ethanol (C2H5OH) solution

containing 1.77 g of ethanol?

The molarity of an 85.0-mL ethanol (C2H5OH) solution containing 1.77 g of ethanol is 0.45M

MOLARITY:

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The molarity of the solution is 0,45 M.

Explanation:

We know that molarity is a concentration measure that expresses moles of solute per liter of solution (1000ml). First we proceed to calculate the mass of 1 mole of compound from the atomic weights of the elements of the periodic table and then we calculate the molarity by a simple rule of three:

Weight 1 mol C2H5OH= (Weight C)x2 + (Weight H)x6 + Weight 0

Weight 1 mol C2H5OH=12 g x 2 + 1g x 6 + 16 g= 46 g/mol

46 g ---1 mol ethanol

1,77gx= (1,77g x  1 mol ethanol)/46 g= 0,038 mol ethanol

85 ml solution0,038 mol ethanol

1000ml solution---x= (1000ml solution x0,038 mol ethanol)/85 ml solution

x=0,45 M---> The solution is 0,45 M

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.