How many moles are there in 0.67 L of a 0.50 M KBr solution?

0.335 moles

Explanation:

Given that,

Amount of moles of KBr solute (n) = ?

Volume of KBr solution (v) = 0.67 L

Concentration of KBr solution (c) = 0.50M

Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence

c = n / v

make n the subject formula

n = c x v

n = 0.50M x 0.67L

n = 0.335 moles

Thus, there are 0.335 moles of KBr in 0.67 L of a 0.50 M KBr solution

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

the maximum mass of nh3 is nh3 in grams