The is inversely proportional to the wavelength and reported in reciprocal centimeters (cm−1). A technique used for measuring the molecular weight and determining the molecular formula of an organic molecule is . A compound that contains an odd number of atoms gives a molecular ion an odd mass. When the molecular ion consists of two peaks (M and M+2) in a 1:1 ratio, a atom is present in the molecule. For a bond to absorb in the IR, there must be a change in the dipole moment during the . Organic chemists use to identify the functional groups in a compound. When the molecular ion consists of two peaks (M and M+2) in a 3:1 ratio, a atom is present in the molecule. The higher the percent s-character, the strong the bond, and the the wavenumber of an IR absorption. Hydrocarbons and compounds that only contain C, H, and O atoms always have a molecular ion with an mass.

Please see below in the explanation column for answers

Explanation:

-The WAVENUMBER is inversely proportional to the wavelength and reported in reciprocal centimeters (cm−1).

- A technique used for measuring the molecular weight and determining the molecular formula of an organic molecule is __MASS SPECTOMETRY .

-A compound that contains an odd number of N atoms gives a molecular ion an odd mass.

-When the molecular ion consists of two peaks (M and M+2) in a 1:1 ratio, a ___Br, Bromine atom is present in the molecule.

-For a bond to absorb in the IR, there must be a change in the dipole moment during the __VIBRATION .

-Organic chemists use iNFRA RED SPECTROSCOPY to identify the functional groups in a compound.

-When the molecular ion consists of two peaks (M and M+2) in a 3:1 ratio, a Cl , chlorine atom is present in the molecule.

- The higher the percent s-character, the strong the bond, and the HIGHER the wavenumber of an IR absorption.

-Hydrocarbons and compounds that only contain C, H, and O atoms always have a molecular ion with an __ EVEN mass.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. these processes are called chemical reactions and, in general, are not reversible except by further chemical reactions. some reactions produce heat and are called exothermic reactions and others may require heat to enable the reaction to occur, which are called endothermic reactions. understanding chemical changes is a major part of the science of chemistry.