Chemistry, 14.04.2020 20:14 kalebbenton15

Ascorbic acid (vitamin C) contains C, H, and O. In one combustion analysis, 5.24 g of ascorbic acid yields 7.86 g CO2 and 2.14 g H2O. Calculate the empirical formula and molecular formula of ascorbic acid given that its molar mass is about 176 g.

Answers: 2

Show answers

Answers

Answer from: lilisncz

Answer : The molecular formula for the given organic compound is C_6H_6O_6

Explanation :

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=7.86g

Mass of H_2O=2.14g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 7.86 g of carbon dioxide, $\frac{12}{44}\times 7.86=2.14g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 2.14 g of water, $\frac{2}{18}\times 2.14=0.238$ of hydrogen will be contained.

Mass of oxygen in the compound = (5.24) - (2.14 + 0.238) = 2.86 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{2.14g}{12g/mole}=0.178moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.238g}{1g/mole}=0.238moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{2.86g}{16g/mole}=0.178moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.178 moles.

For Carbon = $\frac{0.178}{0.178}=1$

For Hydrogen = $\frac{0.238}{0.178}=1.33\approx 1$

For Oxygen = $\frac{0.178}{0.178}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 1 : 1

The empirical formula for the given compound is C_1H_1O_1=CHO

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 176 g/mol

Mass of empirical formula = 29 g/mol

Putting values in above equation, we get:

$n=\frac{176}{29}=6$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 6)}H_{(1\times 6)}O_{(1\times 6)}=C_6H_6O_6$

Thus, the molecular formula for the given organic compound is C_6H_6O_6

Answer from: Quest

While unproven, it uses facts to support part of a conclusion. it is still factual and has predictive power, however.

Answer from: Quest

Hi + naoh -> h2o + nal

Another question on Chemistry

Chemistry, 22.06.2019 05:50

In an exothermic reaction the bonding energy of the product is: less than the reactants same as the reactants greater than the reactants dependent upon the presence of a catalyst

Answers: 1

Answer

Chemistry, 22.06.2019 08:30

What is a metal replacement reaction

Answers: 3

Answer

Chemistry, 22.06.2019 11:20

Which of the following contributes to the structural rigidity of cellulose? adjacent glucose polymers are stabilized by hydrogen bonding. glucose residues are joined by (α1→4) linkages. cellulose is a highly branched molecule. the conformation of the glucose polymer is a coiled structure.

Answers: 2

Answer

Chemistry, 22.06.2019 14:00

What is the molar mass of ca(cio4)2

Answers: 1

Answer

You know the right answer?

Ascorbic acid (vitamin C) contains C, H, and O. In one combustion analysis, 5.24 g of ascorbic acid...

Questions