. A 25.00 mL sample of 0.100 M acetic acid is titrated with 0.100 M NaOH. Consider the titration curve, and predict the main chemical species present after adding 50.00 mL NaOH titrant. Example choices More acetic acid than acetate ion; Equal amounts of acetic acid and acetate ion; More acetate ion than acetic acid; Mainly acetate ion; Mainly the excess titrant

More acetate ion than acetic acid.

Explanation:

Step 1: Data given

Volume of a 0.100 M acetic acid = 25.00 mL = 0.025 L

Volume of a 0.100 M NaOH = 50.00 mL = 0.050 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Moles CH3COOH = 0.100 M * 0.025 L

Moles CH3COOH = 0.0025 moles

Moles NaOH = 0.100 M * 0.050 L

Moles CH3COOH = 0.0050

Step 4: Calculate limiting reactant

CH3COOH is the limiting reactant. It will completely be consumed (0.0025 moles). NaOH is in excess. There will react 0.0025 moles . There will remain 0.0050 - 0.0025 = 0.0025 moles

Step 5: Calculate moles CH3COONa

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 1 mol H2O

For 0.0025 moles CH3COOH we'll have 0.0025 moles CH3COONa  (= CH3COO-)

The acetic acid is completely consumed, so we will have more acetate ion than acetic acid. But the amount of acetate ion is the same as amount of excess titrant.

it's all four options.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.