How many grams of solute are needed to make 5.00 L of 3.00M glucose (molar mass = 180 g/mole)?

2700g glucose

Explanation:

If we want 3 mol/L in 5L we must have 15 moles of glucose because 3 x 5 = 15.

The molar mass of glucose is given as 180 g/mol

to cancel moles from the equation we multiply the molar mass by the number of moles. 180 x 15 = 2700.

2700g glucose

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.