Chemistry, 14.04.2020 21:01 damari9288

Select the statements below that are TRUE. Kc has units of molarity and Kp has units of pressure Kp uses the same equation as Kc, but with pressure instead of concentration If there is a liquid in a reaction, you use the vapor press for that entry in the Kp equation. Kc and Kp are the same thing as the k (rate constant) that you learned about before. Kc is equal to Kp when the number of moles of gas (n) doesn't change. Solids and liquid are not included in the Kc and Kp equations because they have an activity equal to 1.

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Answer from: Hiadamcom

Kp uses the same equation as Kc, but with pressure instead of concentration

Kc is equal to Kp when the number of moles of gas (n) doesn't change.

Solids and liquids are not included in the Kc and Kp equations because they have an activity equal to 1

Explanation:

1. Kc has units of molarity and Kp has units of pressure

FALSE.

Neither Kc nor Kp has units.

2. Kp uses the same equation as Kc, but with pressure instead of concentration

TRUE.

For the reaction A(aq) ⇌ B(aq), the Kc expression is

$K_{\text{c}} = \dfrac{\text{[B]}}{\text{[A]}}$

For the reaction A(g) ⇌ B(g), the Kp expression is

$K_{\text{p}} = \dfrac{p_{\text{B}}}{p_{\text{A}}}$

3. If there is a liquid in a reaction, you use the vapor pressure for that entry in the Kp equation.

FALSE.

If there is a liquid in a reaction, you omit it from both the Kp and Kc expressions.

4. Kc and Kp are the same thing as the k (rate constant) that you learned about before.

FALSE.

Rate constants deal with rates. Equilibrium constants deal with equilibria.

5. Kc is equal to Kp when the number of moles of gas (n) doesn't change.

TRUE

The relation between Kp and Kc is

$K_{\text{p}} = K_{\text{c}}(RT)^{\Delta n}$

If the number of moles of gas doesn't change, Δn = 0.

$K_{\text{p}} = K_{\text{c}}(RT)^{0} = K_{\text{c}}(1) = K_{\text{c}}$

6. Solids and liquids are not included in the Kc and Kp equations because they have an activity equal to 1.

TRUE

Answer from: Quest

law of conservation of matter

Answer from: Quest

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

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Select the statements below that are TRUE. Kc has units of molarity and Kp has units of pressure Kp...

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