Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6Li(s) + N2(g) → 2Li3N(s) How many moles of lithium are needed to produce 0.45 mol of Li3N when the reaction is carried out in the presence of excess nitrogen?

 1.35 moles of are needed to produce 0.45 mol of

Explanation:

The balanced chemical reaction is ;

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry :

2 moles of require = 6 moles of

Thus 0.45 moles of will require= of

Thus 1.35 moles of are needed to produce 0.45 mol of

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