The volume of the lungs is measured by the volume of air inhaled or exhaled. If the volume of the lungs is 2.400 L during exhalation and the pressure is 101.70 KPa, and the pressure during inhalation is 101.01 KPa, what is the volume of the lungs during inhalation?

The volume of the lungs during inhalation is 2.416 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

    (At constant temperature and number of moles)

where,

= initial pressure of gas = 101.70 kPa

= final pressure of gas = 101.01 kPa

= initial volume of gas = 2.400 L

= final volume of gas = ?

Now put all the given values in the above equation, we get the final volume of gas.

Thus the volume of the lungs during inhalation is 2.416 L

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong