A flexible container at an initial volume of 8.15 L contains 8.51 mol of gas. More gas is then added to the container until it reaches a final volume of 16.1 L . Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

8.3 moles

Explanation:

Step 1:

Data obtained from the question. This includes:

Initial volume (V1) = 8.15 L

Initial mole (n1) = 8.51 mol

Final volume (V2) = 16.1 L

Number of mole added =?

Final mole (n2) =?

Step 2:

Obtaining an equation to solve for the final mole. This is illustrated below:

From ideal gas equation,

PV = nRT

Divide both side by P

V = nRT/P

Divide both side by n

V/n = RT/P

Since pressure (P) and temperature (T) are constant, therefore

V/n = constant

V1/n1 = V2/n2

Step 3:

Determination of the final mole. This is illustrated below:

Initial volume (V1) = 8.15 L

Initial mole (n1) = 8.51 mol

Final volume (V2) = 16.1 L

Final mole (n2) =?

V1/n1 = V2/n2

8.15/8.51 = 16.1/n2

Cross multiply to express in linear form

8.15 x n2 = 8.51 x 16.1

Divide both side by 8.15

n2 = (8.51 x 16.1) / 8.15

n2 = 16.81 moles

Therefore, the final mole is 16.81 moles

Step 4:

Determination of the number of moles added. This can be obtained as illustrated below:

Number of mole added = final mole - initial mole

Number of mole added = n2 - n1

Number of mole added = 16.8 - 8.51

Number of mole added = 8.3 moles

When the volume change to 16.1 L; the number of moles increases to 16.8 moles. This means we add 8.29 moles.

Explanation:

Step 1: Data given

The initial volume of the container = 8.15 L

Number of moles of gas= 8.51 moles

The volume increases to 16.1 L

The pressure and temperature of the gas remain constant

Step 2: Calculate the new number of moles

V1/n1 = V2/n2

⇒with V1 = the initial volume in the container = 8.15 L

⇒with n1 = the initial number of gas = 8.51 moles

⇒with V2 = the increased volume = 16.1 L

⇒with n2 = the new number of moles = TO BE DETERMINED

8.15 L / 8.51 moles = 16.1 L / n2

n2 = 16.1 L / (8.15 L / 8.51 moles)

n2 = 16.8 moles

When the volume change to 16.1 L; the number of moles increases to 16.8 moles

The number of moles added = 16.8 - 8.51 = 8.29 moles

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )