Consider the reaction CaCN2 + 3 H2O → CaCO3 + 2 NH3 . This reaction has a 75.6% yield. How many moles of CaCN2 are needed to obtain 18.6 g of NH3?
a. 0.547 mol
b. 209 mol
c. 0.414 mol
d. 1.65 mol
e. 478 mol
f. 0.724 mol

Thus 0.724 mol of are needed to obtain 18.6 g of

Explanation:

To calculate the moles :

According to stoichiometry :

2 moles of are produced by = 1 mole of

Thus 1.09 moles of will be produced by =  of

But as yield of reaction is 75.6 %, the amount of needed is =

Thus 0.724 mol of are needed to obtain 18.6 g of

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)