The energy needed to ionize an atom of si when it is in the most stable is 786.4 kJ mol^-1 however if an atom of Si is in certain low lying excited state only 310.8 is needed to ionize.
what is the wavelength of he radiation emitted when an atom of si undergoes a transition from this excited state to the ground state?

The wavelength of he radiation emitted is

Explanation:

We know that energy needed is given by

 ----- (1)

h = 6.62 × J s

c = 3  ×

E = 786.4 - 310.8 = 475.6

Total energy

E = 78.9 × J

From equation (1)

×

Therefore the wavelength of he radiation emitted is

answer: option (4) is the correct answer.

explanation:

areas which are at low altitudes and near the equator tend to receive direct sunlight from the sun. hence, heat energy or radiations from the sun make these areas warmer and they have warmest water.

whereas areas which are at high altitudes and away from the equator do no receive direct sunlight. hence, no direct contact from the sun makes these regions colder and thus, they have colder water.

thus, we can conclude that the statement areas at low latitudes near the equator have the warmest water because they receive the most direct sunlight best explains the relationship between an area's geography and the temperature of its surface water.

it would be d. henry moseley

hope this !

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