Chemistry, 15.04.2020 03:35 Izzyfizzy

Calculate the binding energy per nucleon for a 157N715N nucleus. The mass of the neutral atom of 157N715N is 15.000109 uu, the mass of the neutral atom of 11H11H is 1.007825 uu and the mass of neutron is 1.008665

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The binding energy per nucleon for a $^{15}_{7}N$ nucleus is 7.7 MeV. It was calculated with the mass of the neutral atom $^{15}_{7}N$ (15.000109 u), the mass of proton ¹H (1.007825 u), and the mass of neutron (1.008665 u).

We can calculate the binding energy per nucleon with the following equation:

$B = \frac{\Delta mc^{2}}{A}$

Where:

c: is the speed of light

A: is the number of nucleons in the nucleus of $^{15}_{7}N$ = 15

We know that 1 u = 931.5 MeV/c², so the binding energy is:

$B = (p*m_{p} + n*m_{n} - m_{^{15}_{7}N})\frac{931.5 MeV/u}{A}$ (1)

Where:

p: is the number of protons = 7

n: is the number of neutrons = A - p = 15 - 7 = 8

$m_{p}$ : is the proton's mass = 1.007825 u

$m_{n}$ : is the neutron's mass = 1.008665 u

$m_{^{15}_{7}N}$ = 15.000109 u

By entering the above values into equation (1), we have:

$B = (7*1.007825 u + 8*1.008665 u - 15.000109 u)\frac{931.5 MeV/u}{15} =7.7 \:MeV/nucleon$

Therefore, the binding energy per nucleon is 7.7 MeV.

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Answer from: vannitling12p4w44f

$1.85\cdot 10^{-11}J$

Explanation:

The binding energy of a nucleus is given by

$\Delta E=c^2 \Delta m$ (1)

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the difference between the sum of the masses of the individual nucleons and the total mass of the nucleus.

Here the mass of the nucleus is

$m(^{15}_7N) = 15.000109 u$

While the mass of the nucleons is:

m(p)=1.007825 u (mass of the proton)

m(n)=1.008665u (mass of the neutron)

The nucleus $^{15}_7N$ containes 7 protons (atomic number) and 15 nucleons (mass number), which means that the number of neutrons is

n=15-7=8

So the mass defect is:

$\Delta m=(7m(p)+8m(n))-m(^{15}_7N)=\\(7\cdot 1.007825+8\cdot 1.008665)-15.000109)=0.123986u$

1 atomic mass unit is

$1 u = 1.66054\cdot 10^{-27}kg$

So the mass defect in kilograms is

$\Delta m=(0.123986)(1.66054\cdot 10^{-27})=2.059\cdot 10^{-28}kg$

Finally, we can use eq(1) to find the binding energy:

$\Delta E=(3\cdot 10^8)^2 (2.059\cdot 10^{-28})=1.85\cdot 10^{-11}J$

Answer from: Quest

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

Answer from: Quest

answer: $2c_5h_5+1fe\rightarrow 1fe(c_5h_5)_2$

the reaction is type of combination reaction.

explanation:

$? c_5h_5+? fe\rightarrow ? fe(c_5h_5)_2$

on the product side, there are 2 molecules of $c_5h_5$ bonded to fe which means one atom of fe are combined two molecules of $c_5h_5$ . so, balanced chemical equation becomes :

$2c_5h_5+1fe\rightarrow 1fe(c_5h_5)_2$

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.

$a+b\rightarrow ab$

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