Diborane (B2H6) is a gas at room temperature that forms explosive mixtures with air. It reacts with oxygen according to the following equation (which may or may not be balanced): B2H6 (g) + O2 (g) → B2O3 (s) + H2O (l) How many grams of O2 (molar mass 32.00 g/mol) will react with 14.67 grams of diborane (molar mass 27.67 g/mol). Your answer must be expressed to the correct number of significant figures, and with the correct unit.

50.91 grams

Explanation:

The balanced chemical equation is :

According to stoichiometry :

1 mole of require  = 3 moles of

Thus 0.5302 moles of will require = of

Mass of

Thus 50.91 grams of reacts with 14.67 g of diborane

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