Write the balanced chemical equation for the neutralization reaction that occurs when an aqueous solution of hydrochloric acid (HCl) is mixed with an aqueous solution of potassium hydroxide (KOH). Indicate the physical states of the reactants and products using the abbreviations (s), (l), (g), or (aq) for solids, liquids, gases, or aqueous solutions, respectively.

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

Explanation:

Aqueous solution of HCl and aqueous solution of KOH react as follow:

HCl(aq) + KOH(aq) —>

In solution, HCl and KOH will dissociates as follow:

HCl —> H+ + Cl-

KOH —> K+ + OH-

During the reaction, a double displacement reaction occur as shown below:

H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-

The elemental equation is given below:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml