URGENT. URGENT. URGENT.
How much heat is required to raise the temperature of 225g of lead from 25⁰C to 60⁰C. The specific heat of lead is 0.128J/(g⁰C).
Please show all work for full credit.

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A piece of unknown metal has a heat capacity of 222 J for 1⁰C and a mass of 246 g. Calculate the specific heat of this metal. Identify the metal. Please show all work for full credit.

Explanation:

1)

Given data:

Heat required = ?

Mass of sample = 225 g

Initial temperature = 25°C

Final temperature = 60°C

Specific heat capacity of lead = 0.128 j/g°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  60°C - 25°C

ΔT = 35°C

Q = 225 g × 0.128 j/g°C × 35°C

Q = 1008 j

2)

Given data:

Heat capacity for 1°C = 222 j

Mass of sample = 246 g

Specific heat capacity of sample = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

222 j = 246 g × c × 1°C

c = 222 j / 246 g.°C

c = 0.902 j/g.°C

The given metal is aluminium.