Suppose 50.0 ml of 0.350 m lithium hydroxide is mixed with 30.0 ml of 0.250 m perchloric acid. What is the ph of the resulting solution

The pH of the resulting solution is 13.1

Explanation:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 0.350 M

Volume of solution = 50.0 mL

Putting values in equation 1, we get:

a)

1 mole of contains = 1 mol of

Thus of contain= mol of

1 mole of contains = 1 mol of

Thus of contain= mol of

As 1 mole of combines with 1 mole of

0.0075 moles of combines with = 0.0075 mole of

Moles of left = (0.0175-0.0075) = 0.01

Moles of left =

pOH =

pOH =

Thus the ph of the resulting solution is 13.1