If 85 g of KBr were dissolved in 100g of water at 60°C, the solution would be
240
220
200
180
160
NaCIOS
140
Solubility
(g/100 g of H20)
KBr
NaCI
20
40
100
120
60 80
Temperature
(C)

Explanation:

The data are garbled and difficult to decipher so i have to work with other data.

I will use the graph attached.

There, I have drawn two red lines that intersect at T = 60ºC and Solubility close the the middle point between 80 and 90 g/100g of H₂O, but a little bit above (closer to 90 than to 80 g/100g of H₂O).

That means that the solubility at 60ºC is close to 85g/100g of H₂O but a little bit above.

Then, if 85 g of KBr were dissolved in 100g of water at 60°C, the solution would be unsaturated: it can dissolve a little bit more of solute.

To understand how you use the solubility curve graphs:

For a given temperature:

58750.08068 is the answer i think

po-215 i got it right on the quiz