Calculate the quantity of energy produced per gram of reactant for the fusion of HH-3 (atomic mass = 3.016049 amuamu) with HH-1 (atomic mass =1.007825 amuamu) to form HeHe-4 (atomic mass = 4.002603 amuamu). (31H+11H→42He13H+11H→24He) Express your answer using five significant figures.

it is a good conductor

explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

answer: i dont know the answer but this might

explanation:

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