N2 +3H2 → 2NH3 What volume of ammonia at STP is produced if 30.0 g of nitrogen gas is reacted with an excess of hydrogen gas?

V= 48L

Explanation:

Moles of N2 = m/M = 30/28= 1.07moles

From the equation of reaction

N2 +3H2 → 2NH3

1mole of N2 produces 2mole of NH3

Hence

1.07moles will produce 1.07×2= 2.14 moles

At STP, 1mole occupy 22.4L

Hence volume of N2 produced = 2.14×22.4= 48 L

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).