How much of a 0.250 M sucrose solution must be used to prepare 400.0 mL of a 0.0310 M solution?

Which statement best explains how the solution should be made?

What is the molarity of the solution that results when 25.0 mL of 0.513 M solution is diluted to 500.0 mL?

ANSWER: 49.6 mL

Which statement best explains how the solution should be made?

ANSWER: Add 49.6 mL of 0.250 M sucrose to 350.4 mL of water to get 400.0 mL of 0.0310 M sucrose.

what is the molarity of the solution that results when 25.0 mL of 0.513 M solution is deluted to 500.0 mL?
ANSWER: 0.0257 M

i would say b

explanation:

but i think i would need more information than that

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2